
Bryan
Cole
1.
First,
bromoethane reacts with NaC2H to form a 4-carbon terminal alkyne.
2.
This
reacts with sodium in liquid nitrogen to form a terminal alkene
3.
This
reacts with a Br-radical, in the presence of peroxide, to add a bromine to the
end of the chain, in the anti-Markovnikov fashion.
4.
This
will react in the same manner as the first reaction to form a 6-carbon terminal
alkyne.
5.
We
can react this alkyne with NaNH2 and bromoethane to form 3-octyne.
6.
In
the last step, we convert the triple bond to a trans double bond by using sodium in liquid ammonia.