Beginning Problem 28 on p. 34

n=10

t

S

k

d=difference

(initial)

t=a

S=a

k=1

 

10

t+d=a+d

S+t=a+(a+d)=2a+d

2

 

10

t+d=a+2d

S+t=3a+3d

3

 

10

t+d=a+3d

S+t=4a+6d

4

 

10

t+d=a+4d

S+t=5a+10d

5

 

10

 

 

6

 

10

 

 

7

 

10

 

 

8

 

10

 

 

9

 

 

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